Base | Representation |
---|---|
bin | 111100111011001000… |
… | …0011100101001111111 |
3 | 110111200222110011110222 |
4 | 1321312100130221333 |
5 | 4120421224321142 |
6 | 140034234051555 |
7 | 12311110336241 |
oct | 1716620345177 |
9 | 414628404428 |
10 | 130833042047 |
11 | 50538928a34 |
12 | 21433879bbb |
13 | c450656216 |
14 | 6491d96091 |
15 | 360b065bd2 |
hex | 1e7641ca7f |
130833042047 has 2 divisors, whose sum is σ = 130833042048. Its totient is φ = 130833042046.
The previous prime is 130833041993. The next prime is 130833042071. The reversal of 130833042047 is 740240338031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130833042047 is a prime.
It is a super-3 number, since 3×1308330420473 (a number of 34 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 130833041998 and 130833042016.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130833042247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65416521023 + 65416521024.
It is an arithmetic number, because the mean of its divisors is an integer number (65416521024).
Almost surely, 2130833042047 is an apocalyptic number.
130833042047 is a deficient number, since it is larger than the sum of its proper divisors (1).
130833042047 is an equidigital number, since it uses as much as digits as its factorization.
130833042047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48384, while the sum is 35.
The spelling of 130833042047 in words is "one hundred thirty billion, eight hundred thirty-three million, forty-two thousand, forty-seven".
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