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1308376484873 is a prime number
BaseRepresentation
bin10011000010100001010…
…100001100110000001001
311122002011000011222021122
4103002201110030300021
5132414023340003443
62441020532445025
7163345534424153
oct23024124146011
94562130158248
101308376484873
11464974464267
121916a4779775
13964c1637773
144747bc55ad3
15240794db968
hex130a150cc09

1308376484873 has 2 divisors, whose sum is σ = 1308376484874. Its totient is φ = 1308376484872.

The previous prime is 1308376484867. The next prime is 1308376484929. The reversal of 1308376484873 is 3784846738031.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 731372171209 + 577004313664 = 855203^2 + 759608^2 .

It is a cyclic number.

It is not a de Polignac number, because 1308376484873 - 218 = 1308376222729 is a prime.

It is a super-2 number, since 2×13083764848732 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1308376484843) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 654188242436 + 654188242437.

It is an arithmetic number, because the mean of its divisors is an integer number (654188242437).

Almost surely, 21308376484873 is an apocalyptic number.

It is an amenable number.

1308376484873 is a deficient number, since it is larger than the sum of its proper divisors (1).

1308376484873 is an equidigital number, since it uses as much as digits as its factorization.

1308376484873 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 65028096, while the sum is 62.

The spelling of 1308376484873 in words is "one trillion, three hundred eight billion, three hundred seventy-six million, four hundred eighty-four thousand, eight hundred seventy-three".