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1308410421137 is a prime number
BaseRepresentation
bin10011000010100011010…
…101101001111110010001
311122002020101001010002022
4103002203111221332101
5132414111031434022
62441024144101225
7163346426035541
oct23024325517621
94562211033068
101308410421137
11464991633066
121916b4004815
13964c868a2b1
144748256b321
152407c491c42
hex130a3569f91

1308410421137 has 2 divisors, whose sum is σ = 1308410421138. Its totient is φ = 1308410421136.

The previous prime is 1308410421107. The next prime is 1308410421173. The reversal of 1308410421137 is 7311240148031.

Together with next prime (1308410421173) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1150419275776 + 157991145361 = 1072576^2 + 397481^2 .

It is a cyclic number.

It is not a de Polignac number, because 1308410421137 - 226 = 1308343312273 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1308410421097 and 1308410421106.

It is not a weakly prime, because it can be changed into another prime (1308410421107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 654205210568 + 654205210569.

It is an arithmetic number, because the mean of its divisors is an integer number (654205210569).

Almost surely, 21308410421137 is an apocalyptic number.

It is an amenable number.

1308410421137 is a deficient number, since it is larger than the sum of its proper divisors (1).

1308410421137 is an equidigital number, since it uses as much as digits as its factorization.

1308410421137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16128, while the sum is 35.

Adding to 1308410421137 its reverse (7311240148031), we get a palindrome (8619650569168).

The spelling of 1308410421137 in words is "one trillion, three hundred eight billion, four hundred ten million, four hundred twenty-one thousand, one hundred thirty-seven".