Base | Representation |
---|---|
bin | 111100111011011101… |
… | …0010000000000110111 |
3 | 110111201202001220101121 |
4 | 1321312322100000313 |
5 | 4120432031002221 |
6 | 140035305004411 |
7 | 12311302436443 |
oct | 1716672200067 |
9 | 414652056347 |
10 | 130844000311 |
11 | 50544033052 |
12 | 21437483707 |
13 | c4529c1cbb |
14 | 6493609823 |
15 | 360becca41 |
hex | 1e76e90037 |
130844000311 has 2 divisors, whose sum is σ = 130844000312. Its totient is φ = 130844000310.
The previous prime is 130844000303. The next prime is 130844000387. The reversal of 130844000311 is 113000448031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130844000311 - 23 = 130844000303 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130844007311) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65422000155 + 65422000156.
It is an arithmetic number, because the mean of its divisors is an integer number (65422000156).
Almost surely, 2130844000311 is an apocalyptic number.
130844000311 is a deficient number, since it is larger than the sum of its proper divisors (1).
130844000311 is an equidigital number, since it uses as much as digits as its factorization.
130844000311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 130844000311 its reverse (113000448031), we get a palindrome (243844448342).
The spelling of 130844000311 in words is "one hundred thirty billion, eight hundred forty-four million, three hundred eleven", and thus it is an aban number.
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