Search a number
-
+
13090535313001 is a prime number
BaseRepresentation
bin1011111001111110000010…
…1101010000111001101001
31201100102221220122221210021
42332133200231100321221
53203433404020004001
643501413042320441
72520521445146266
oct276374055207151
951312856587707
1013090535313001
114197734a07423
121575049959121
1373c580677b43
1433382a06c26d
1517a7aca04ba1
hexbe7e0b50e69

13090535313001 has 2 divisors, whose sum is σ = 13090535313002. Its totient is φ = 13090535313000.

The previous prime is 13090535312999. The next prime is 13090535313007. The reversal of 13090535313001 is 10031353509031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12110086802025 + 980448510976 = 3479955^2 + 990176^2 .

It is an emirp because it is prime and its reverse (10031353509031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13090535313001 - 21 = 13090535312999 is a prime.

It is a super-2 number, since 2×130905353130012 (a number of 27 digits) contains 22 as substring.

Together with 13090535312999, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (13090535313007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6545267656500 + 6545267656501.

It is an arithmetic number, because the mean of its divisors is an integer number (6545267656501).

Almost surely, 213090535313001 is an apocalyptic number.

It is an amenable number.

13090535313001 is a deficient number, since it is larger than the sum of its proper divisors (1).

13090535313001 is an equidigital number, since it uses as much as digits as its factorization.

13090535313001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18225, while the sum is 34.

The spelling of 13090535313001 in words is "thirteen trillion, ninety billion, five hundred thirty-five million, three hundred thirteen thousand, one".