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13099775917 is a prime number
BaseRepresentation
bin11000011001100111…
…01011011110101101
31020210221112120021211
430030303223132231
5203312020312132
610003513354421
7642424154344
oct141463533655
936727476254
1013099775917
115612533598
122657108a11
131309c674c7
148c3adcb5b
1551a0b0147
hex30cceb7ad

13099775917 has 2 divisors, whose sum is σ = 13099775918. Its totient is φ = 13099775916.

The previous prime is 13099775911. The next prime is 13099775921. The reversal of 13099775917 is 71957799031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10976962441 + 2122813476 = 104771^2 + 46074^2 .

It is an emirp because it is prime and its reverse (71957799031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13099775917 is a prime.

It is a super-2 number, since 2×130997759172 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13099775911) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6549887958 + 6549887959.

It is an arithmetic number, because the mean of its divisors is an integer number (6549887959).

Almost surely, 213099775917 is an apocalyptic number.

It is an amenable number.

13099775917 is a deficient number, since it is larger than the sum of its proper divisors (1).

13099775917 is an equidigital number, since it uses as much as digits as its factorization.

13099775917 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3750705, while the sum is 58.

The spelling of 13099775917 in words is "thirteen billion, ninety-nine million, seven hundred seventy-five thousand, nine hundred seventeen".