13100003411241 has 4 divisors (see below), whose sum is σ = 17466671214992. Its totient is φ = 8733335607492.

The previous prime is 13100003411219. The next prime is 13100003411249. The reversal of 13100003411241 is 14211430000131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13100003411241 - 2⁷ = 13100003411113 is a prime.

It is a super-2 number, since 2×13100003411241² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13100003411249) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2183333901871 + ... + 2183333901876.

It is an arithmetic number, because the mean of its divisors is an integer number (4366667803748).

Almost surely, 2^{13100003411241} is an apocalyptic number.

It is an amenable number.

13100003411241 is a deficient number, since it is larger than the sum of its proper divisors (4366667803751).

13100003411241 is an equidigital number, since it uses as much as digits as its factorization.

13100003411241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4366667803750.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 13100003411241 its reverse (14211430000131), we get a palindrome (27311433411372).

The spelling of 13100003411241 in words is "thirteen trillion, one hundred billion, three million, four hundred eleven thousand, two hundred forty-one".