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131000042010003 = 343666680670001
BaseRepresentation
bin11101110010010011010010…
…111110000011010110010011
3122011211111000011111001010220
4131302103102332003112103
5114132301041223310003
61142340331040524123
736410304106426605
oct3562232276032623
9564744004431126
10131000042010003
1138816895606931
1212838829020643
13581333546c3ca
14244c61601d175
15102292985c353
hex7724d2f83593

131000042010003 has 4 divisors (see below), whose sum is σ = 174666722680008. Its totient is φ = 87333361340000.

The previous prime is 131000042009987. The next prime is 131000042010041. The reversal of 131000042010003 is 300010240000131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131000042010003 - 24 = 131000042009987 is a prime.

It is a super-2 number, since 2×1310000420100032 (a number of 29 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (131000042010073) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21833340334998 + ... + 21833340335003.

It is an arithmetic number, because the mean of its divisors is an integer number (43666680670002).

Almost surely, 2131000042010003 is an apocalyptic number.

131000042010003 is a deficient number, since it is larger than the sum of its proper divisors (43666680670005).

131000042010003 is an equidigital number, since it uses as much as digits as its factorization.

131000042010003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43666680670004.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 131000042010003 its reverse (300010240000131), we get a palindrome (431010282010134).

The spelling of 131000042010003 in words is "one hundred thirty-one trillion, forty-two million, ten thousand, three".

Divisors: 1 3 43666680670001 131000042010003