131000042403133 has 2 divisors, whose sum is σ = 131000042403134. Its totient is φ = 131000042403132.

The previous prime is 131000042403107. The next prime is 131000042403281. The reversal of 131000042403133 is 331304240000131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 100060049012004 + 30939993391129 = 10003002^2 + 5562373^2 .

It is a cyclic number.

It is not a de Polignac number, because 131000042403133 - 2⁵ = 131000042403101 is a prime.

It is a super-2 number, since 2×131000042403133² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131000042403098 and 131000042403107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131000042403733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500021201566 + 65500021201567.

It is an arithmetic number, because the mean of its divisors is an integer number (65500021201567).

Almost surely, 2^{131000042403133} is an apocalyptic number.

It is an amenable number.

131000042403133 is a deficient number, since it is larger than the sum of its proper divisors (1).

131000042403133 is an equidigital number, since it uses as much as digits as its factorization.

131000042403133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 131000042403133 its reverse (331304240000131), we get a palindrome (462304282403264).

The spelling of 131000042403133 in words is "one hundred thirty-one trillion, forty-two million, four hundred three thousand, one hundred thirty-three".