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1310000563 is a prime number
BaseRepresentation
bin100111000010101…
…0000010110110011
310101021222220221101
41032011100112303
510140330004223
6333553505231
744314551424
oct11605202663
93337886841
101310000563
116125088a3
12306872217
1317b529b81
14c5da564b
157a0184ad
hex4e1505b3

1310000563 has 2 divisors, whose sum is σ = 1310000564. Its totient is φ = 1310000562.

The previous prime is 1310000539. The next prime is 1310000579. The reversal of 1310000563 is 3650000131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1310000563 - 29 = 1310000051 is a prime.

It is a super-2 number, since 2×13100005632 = 3432202950120633938, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1310000563.

It is not a weakly prime, because it can be changed into another prime (1310000513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655000281 + 655000282.

It is an arithmetic number, because the mean of its divisors is an integer number (655000282).

Almost surely, 21310000563 is an apocalyptic number.

1310000563 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310000563 is an equidigital number, since it uses as much as digits as its factorization.

1310000563 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 270, while the sum is 19.

The square root of 1310000563 is about 36193.9299192558. The cubic root of 1310000563 is about 1094.1843381130.

Adding to 1310000563 its reverse (3650000131), we get a palindrome (4960000694).

The spelling of 1310000563 in words is "one billion, three hundred ten million, five hundred sixty-three", and thus it is an aban number.