Base | Representation |
---|---|
bin | 10011000100000010001… |
… | …001001111001110010011 |
3 | 11122020100012222221222001 |
4 | 103010002021033032103 |
5 | 132430340224020423 |
6 | 2441450043454431 |
7 | 163434021533635 |
oct | 23040211171623 |
9 | 4566305887861 |
10 | 1310001001363 |
11 | 46562846057a |
12 | 191a78827417 |
13 | 966c0075622 |
14 | 475938cca55 |
15 | 24121e2ecad |
hex | 1310224f393 |
1310001001363 has 2 divisors, whose sum is σ = 1310001001364. Its totient is φ = 1310001001362.
The previous prime is 1310001001343. The next prime is 1310001001423. The reversal of 1310001001363 is 3631001000131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1310001001363 is a prime.
It is a super-2 number, since 2×13100010013632 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1310001001363.
It is not a weakly prime, because it can be changed into another prime (1310001001343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655000500681 + 655000500682.
It is an arithmetic number, because the mean of its divisors is an integer number (655000500682).
Almost surely, 21310001001363 is an apocalyptic number.
1310001001363 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310001001363 is an equidigital number, since it uses as much as digits as its factorization.
1310001001363 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 1310001001363 its reverse (3631001000131), we get a palindrome (4941002001494).
The spelling of 1310001001363 in words is "one trillion, three hundred ten billion, one million, one thousand, three hundred sixty-three".
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