1310001001403 has 16 divisors (see below), whose sum is σ = 1331435458560. Its totient is φ = 1288696219200.

The previous prime is 1310001001363. The next prime is 1310001001423. The reversal of 1310001001403 is 3041001000131.

It is a cyclic number.

It is not a de Polignac number, because 1310001001403 - 2²² = 1309996807099 is a prime.

It is a super-2 number, since 2×1310001001403² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1310001001423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 24920918 + ... + 24973428.

It is an arithmetic number, because the mean of its divisors is an integer number (83214716160).

Almost surely, 2^{1310001001403} is an apocalyptic number.

1310001001403 is a deficient number, since it is larger than the sum of its proper divisors (21434457157).

1310001001403 is an equidigital number, since it uses as much as digits as its factorization.

1310001001403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 53738.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 1310001001403 its reverse (3041001000131), we get a palindrome (4351002001534).

The spelling of 1310001001403 in words is "one trillion, three hundred ten billion, one million, one thousand, four hundred three".