Base | Representation |
---|---|
bin | 10011000100000010001… |
… | …001001111001110111010 |
3 | 11122020100012222222000111 |
4 | 103010002021033032322 |
5 | 132430340224021102 |
6 | 2441450043454534 |
7 | 163434021534022 |
oct | 23040211171672 |
9 | 4566305888014 |
10 | 1310001001402 |
11 | 465628460605 |
12 | 191a7882744a |
13 | 966c0075652 |
14 | 475938cca82 |
15 | 24121e2ecd7 |
hex | 1310224f3ba |
1310001001402 has 8 divisors (see below), whose sum is σ = 1967734468800. Its totient is φ = 654089511804.
The previous prime is 1310001001363. The next prime is 1310001001423. The reversal of 1310001001402 is 2041001000131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-3 number, since 3×13100010014023 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 455492652 + ... + 455495527.
It is an arithmetic number, because the mean of its divisors is an integer number (245966808600).
Almost surely, 21310001001402 is an apocalyptic number.
1310001001402 is a deficient number, since it is larger than the sum of its proper divisors (657733467398).
1310001001402 is an equidigital number, since it uses as much as digits as its factorization.
1310001001402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 910988900.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 1310001001402 its reverse (2041001000131), we get a palindrome (3351002001533).
The spelling of 1310001001402 in words is "one trillion, three hundred ten billion, one million, one thousand, four hundred two".
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