Base | Representation |
---|---|
bin | 11000011001101001… |
… | …00101001001101110 |
3 | 1020210221222120022220 |
4 | 30030310211021232 |
5 | 203312100342032 |
6 | 10003522420210 |
7 | 642426160140 |
oct | 141464451156 |
9 | 36727876286 |
10 | 13100012142 |
11 | 5612685018 |
12 | 2657201666 |
13 | 130a01ab99 |
14 | 8c3b60c90 |
15 | 51a10a12c |
hex | 30cd2526e |
13100012142 has 32 divisors (see below), whose sum is σ = 29946868992. Its totient is φ = 3742362624.
The previous prime is 13100012129. The next prime is 13100012179. The reversal of 13100012142 is 24121000131.
It is a super-2 number, since 2×131000121422 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 398173 + ... + 429815.
It is an arithmetic number, because the mean of its divisors is an integer number (935839656).
Almost surely, 213100012142 is an apocalyptic number.
13100012142 is an abundant number, since it is smaller than the sum of its proper divisors (16846856850).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13100012142 is a wasteful number, since it uses less digits than its factorization.
13100012142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41512.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 13100012142 its reverse (24121000131), we get a palindrome (37221012273).
The spelling of 13100012142 in words is "thirteen billion, one hundred million, twelve thousand, one hundred forty-two".
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