13100012141 has 4 divisors (see below), whose sum is σ = 13168598784. Its totient is φ = 13031425500.

The previous prime is 13100012129. The next prime is 13100012179. The reversal of 13100012141 is 14121000131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13100012141 - 2¹⁴ = 13099995757 is a prime.

It is a super-2 number, since 2×13100012141² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13100012111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34293035 + ... + 34293416.

It is an arithmetic number, because the mean of its divisors is an integer number (3292149696).

Almost surely, 2^13100012141 is an apocalyptic number.

It is an amenable number.

13100012141 is a deficient number, since it is larger than the sum of its proper divisors (68586643).

13100012141 is an equidigital number, since it uses as much as digits as its factorization.

13100012141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 68586642.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 13100012141 its reverse (14121000131), we get a palindrome (27221012272).

The spelling of 13100012141 in words is "thirteen billion, one hundred million, twelve thousand, one hundred forty-one".