131000196947 has 2 divisors, whose sum is σ = 131000196948. Its totient is φ = 131000196946.

The previous prime is 131000196941. The next prime is 131000196949. The reversal of 131000196947 is 749691000131.

It is a strong prime.

It is an emirp because it is prime and its reverse (749691000131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131000196947 - 2⁶ = 131000196883 is a prime.

It is a super-2 number, since 2×131000196947² (a number of 23 digits) contains 22 as substring.

Together with 131000196949, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (131000196941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500098473 + 65500098474.

It is an arithmetic number, because the mean of its divisors is an integer number (65500098474).

Almost surely, 2^131000196947 is an apocalyptic number.

131000196947 is a deficient number, since it is larger than the sum of its proper divisors (1).

131000196947 is an equidigital number, since it uses as much as digits as its factorization.

131000196947 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40824, while the sum is 41.

The spelling of 131000196947 in words is "one hundred thirty-one billion, one hundred ninety-six thousand, nine hundred forty-seven".