Base | Representation |
---|---|
bin | 1011111010100001011000… |
… | …0001100001010010110011 |
3 | 1201101100102220022021112011 |
4 | 2332220112001201102303 |
5 | 3204112320024000232 |
6 | 43510022130543351 |
7 | 2521305462425305 |
oct | 276502601412263 |
9 | 51340386267464 |
10 | 13100019750067 |
11 | 41a07616a5368 |
12 | 1576a56137b57 |
13 | 7404325c1593 |
14 | 334089947975 |
15 | 17ab654c3547 |
hex | bea160614b3 |
13100019750067 has 2 divisors, whose sum is σ = 13100019750068. Its totient is φ = 13100019750066.
The previous prime is 13100019750061. The next prime is 13100019750073. The reversal of 13100019750067 is 76005791000131.
It is a balanced prime because it is at equal distance from previous prime (13100019750061) and next prime (13100019750073).
It is a cyclic number.
It is not a de Polignac number, because 13100019750067 - 231 = 13097872266419 is a prime.
It is a super-2 number, since 2×131000197500672 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13100019750061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550009875033 + 6550009875034.
It is an arithmetic number, because the mean of its divisors is an integer number (6550009875034).
Almost surely, 213100019750067 is an apocalyptic number.
13100019750067 is a deficient number, since it is larger than the sum of its proper divisors (1).
13100019750067 is an equidigital number, since it uses as much as digits as its factorization.
13100019750067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 39690, while the sum is 40.
The spelling of 13100019750067 in words is "thirteen trillion, one hundred billion, nineteen million, seven hundred fifty thousand, sixty-seven".
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