Base | Representation |
---|---|
bin | 11101110010010011011100… |
… | …101000000111001111101001 |
3 | 122011211111102110100120002211 |
4 | 131302103130220013033221 |
5 | 114132301404212442303 |
6 | 1142340355105325121 |
7 | 36410311114534105 |
oct | 3562233450071751 |
9 | 564744373316084 |
10 | 131000204030953 |
11 | 38816969009644 |
12 | 128388733367a1 |
13 | 581335cbb99aa |
14 | 244c62d756905 |
15 | 1022938bb366d |
hex | 7724dca073e9 |
131000204030953 has 2 divisors, whose sum is σ = 131000204030954. Its totient is φ = 131000204030952.
The previous prime is 131000204030933. The next prime is 131000204031133. The reversal of 131000204030953 is 359030402000131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 84782328583824 + 46217875447129 = 9207732^2 + 6798373^2 .
It is a cyclic number.
It is not a de Polignac number, because 131000204030953 - 25 = 131000204030921 is a prime.
It is a super-2 number, since 2×1310002040309532 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131000204030933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500102015476 + 65500102015477.
It is an arithmetic number, because the mean of its divisors is an integer number (65500102015477).
Almost surely, 2131000204030953 is an apocalyptic number.
It is an amenable number.
131000204030953 is a deficient number, since it is larger than the sum of its proper divisors (1).
131000204030953 is an equidigital number, since it uses as much as digits as its factorization.
131000204030953 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9720, while the sum is 31.
The spelling of 131000204030953 in words is "one hundred thirty-one trillion, two hundred four million, thirty thousand, nine hundred fifty-three".
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