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131000204031133 is a prime number
BaseRepresentation
bin11101110010010011011100…
…101000000111010010011101
3122011211111102110100120100111
4131302103130220013102131
5114132301404212444013
61142340355105330021
736410311114534453
oct3562233450072235
9564744373316314
10131000204031133
1138816969009798
1212838873336911
13581335cbb9ab8
14244c62d7569d3
151022938bb373d
hex7724dca0749d

131000204031133 has 2 divisors, whose sum is σ = 131000204031134. Its totient is φ = 131000204031132.

The previous prime is 131000204030953. The next prime is 131000204031157. The reversal of 131000204031133 is 331130402000131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 99339753426489 + 31660450604644 = 9966933^2 + 5626762^2 .

It is a cyclic number.

It is not a de Polignac number, because 131000204031133 - 225 = 131000170476701 is a prime.

It is a super-2 number, since 2×1310002040311332 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131000204031233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500102015566 + 65500102015567.

It is an arithmetic number, because the mean of its divisors is an integer number (65500102015567).

Almost surely, 2131000204031133 is an apocalyptic number.

It is an amenable number.

131000204031133 is a deficient number, since it is larger than the sum of its proper divisors (1).

131000204031133 is an equidigital number, since it uses as much as digits as its factorization.

131000204031133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 131000204031133 its reverse (331130402000131), we get a palindrome (462130606031264).

The spelling of 131000204031133 in words is "one hundred thirty-one trillion, two hundred four million, thirty-one thousand, one hundred thirty-three".