Base | Representation |
---|---|
bin | 1011111010100001011000… |
… | …1010010000101010011011 |
3 | 1201101100110001121200102112 |
4 | 2332220112022100222123 |
5 | 3204112321120304433 |
6 | 43510022252022535 |
7 | 2521305521050154 |
oct | 276502612205233 |
9 | 51340401550375 |
10 | 13100022041243 |
11 | 41a0762a1a7a5 |
12 | 1576a56a61a4b |
13 | 740432c143c7 |
14 | 334089d8292b |
15 | 17ab657c7348 |
hex | bea16290a9b |
13100022041243 has 4 divisors (see below), whose sum is σ = 13100050103400. Its totient is φ = 13099993979088.
The previous prime is 13100022041221. The next prime is 13100022041251. The reversal of 13100022041243 is 34214022000131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13100022041243 - 230 = 13098948299419 is a prime.
It is a super-2 number, since 2×131000220412432 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13100022041213) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13318793 + ... + 14268506.
It is an arithmetic number, because the mean of its divisors is an integer number (3275012525850).
Almost surely, 213100022041243 is an apocalyptic number.
13100022041243 is a deficient number, since it is larger than the sum of its proper divisors (28062157).
13100022041243 is an equidigital number, since it uses as much as digits as its factorization.
13100022041243 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28062156.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 13100022041243 its reverse (34214022000131), we get a palindrome (47314044041374).
The spelling of 13100022041243 in words is "thirteen trillion, one hundred billion, twenty-two million, forty-one thousand, two hundred forty-three".
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