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13100023003 = 48012728603
BaseRepresentation
bin11000011001101001…
…00111110011011011
31020210222000010020011
430030310213303123
5203312101214003
610003522542351
7642426233614
oct141464476333
936728003204
1013100023003
1156126921a1
1226572079b7
13130a022b02
148c3b64c0b
1551a10d46d
hex30cd27cdb

13100023003 has 4 divisors (see below), whose sum is σ = 13102756408. Its totient is φ = 13097289600.

The previous prime is 13100022913. The next prime is 13100023007. The reversal of 13100023003 is 30032000131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13100023003 is a prime.

It is a super-2 number, since 2×131000230032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13100023007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1359501 + ... + 1369102.

It is an arithmetic number, because the mean of its divisors is an integer number (3275689102).

Almost surely, 213100023003 is an apocalyptic number.

13100023003 is a deficient number, since it is larger than the sum of its proper divisors (2733405).

13100023003 is an equidigital number, since it uses as much as digits as its factorization.

13100023003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2733404.

The product of its (nonzero) digits is 54, while the sum is 13.

Adding to 13100023003 its reverse (30032000131), we get a palindrome (43132023134).

The spelling of 13100023003 in words is "thirteen billion, one hundred million, twenty-three thousand, three".

Divisors: 1 4801 2728603 13100023003