Base | Representation |
---|---|
bin | 11101110010010011100010… |
… | …100101011101110000000000 |
3 | 122011211111200102110111212010 |
4 | 131302103202211131300000 |
5 | 114132302110311000000 |
6 | 1142340413040132520 |
7 | 36410313440340051 |
oct | 3562234245356000 |
9 | 564744612414763 |
10 | 131000304000000 |
11 | 38816a0a489896 |
12 | 128388a0907140 |
13 | 581337781c386 |
14 | 244c63cb3a728 |
15 | 102294285dd50 |
hex | 7724e295dc00 |
131000304000000 has 308 divisors, whose sum is σ = 436449036662072. Its totient is φ = 34933401600000.
The previous prime is 131000303999977. The next prime is 131000304000019. The reversal of 131000304000000 is 403000131.
It is a super-2 number, since 2×1310003040000002 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (12).
It is a self number, because there is not a number n which added to its sum of digits gives 131000304000000.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 27 ways as a sum of consecutive naturals, for example, 46635414 + ... + 49364586.
Almost surely, 2131000304000000 is an apocalyptic number.
131000304000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131000304000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (218224518331036).
131000304000000 is an abundant number, since it is smaller than the sum of its proper divisors (305448732662072).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131000304000000 is an frugal number, since it uses more digits than its factorization.
131000304000000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2729226 (or 2729183 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 12.
Adding to 131000304000000 its reverse (403000131), we get a palindrome (131000707000131).
The spelling of 131000304000000 in words is "one hundred thirty-one trillion, three hundred four million", and thus it is an aban number.
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