Base | Representation |
---|---|
bin | 11101110010010011100010… |
… | …100101100001000001011001 |
3 | 122011211111200102111012020110 |
4 | 131302103202211201001121 |
5 | 114132302110311412101 |
6 | 1142340413040314533 |
7 | 36410313440424114 |
oct | 3562234245410131 |
9 | 564744612435213 |
10 | 131000304013401 |
11 | 38816a0a498969 |
12 | 128388a0912a49 |
13 | 58133778254c4 |
14 | 244c63cb4157b |
15 | 1022942862cd6 |
hex | 7724e2961059 |
131000304013401 has 16 divisors (see below), whose sum is σ = 182335776344064. Its totient is φ = 83502287337744.
The previous prime is 131000304013387. The next prime is 131000304013427. The reversal of 131000304013401 is 104310403000131.
It is not a de Polignac number, because 131000304013401 - 27 = 131000304013273 is a prime.
It is a super-2 number, since 2×1310003040134012 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (131000304012401) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 387766411 + ... + 388104096.
It is an arithmetic number, because the mean of its divisors is an integer number (11395986021504).
Almost surely, 2131000304013401 is an apocalyptic number.
It is an amenable number.
131000304013401 is a deficient number, since it is larger than the sum of its proper divisors (51335472330663).
131000304013401 is a wasteful number, since it uses less digits than its factorization.
131000304013401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 775872980.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 131000304013401 its reverse (104310403000131), we get a palindrome (235310707013532).
The spelling of 131000304013401 in words is "one hundred thirty-one trillion, three hundred four million, thirteen thousand, four hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •