Base | Representation |
---|---|
bin | 11101110010010011100010… |
… | …100101100101101000101110 |
3 | 122011211111200102112011011111 |
4 | 131302103202211211220232 |
5 | 114132302110313013202 |
6 | 1142340413040542234 |
7 | 36410313440533165 |
oct | 3562234245455056 |
9 | 564744612464144 |
10 | 131000304032302 |
11 | 38816a0a501091 |
12 | 128388a092197a |
13 | 5813377830ca3 |
14 | 244c63cb483dc |
15 | 10229428686d7 |
hex | 7724e2965a2e |
131000304032302 has 4 divisors (see below), whose sum is σ = 196500456048456. Its totient is φ = 65500152016150.
The previous prime is 131000304032293. The next prime is 131000304032309. The reversal of 131000304032302 is 203230403000131.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×1310003040323022 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131000304032309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32750076008074 + ... + 32750076008077.
It is an arithmetic number, because the mean of its divisors is an integer number (49125114012114).
Almost surely, 2131000304032302 is an apocalyptic number.
131000304032302 is a deficient number, since it is larger than the sum of its proper divisors (65500152016154).
131000304032302 is an equidigital number, since it uses as much as digits as its factorization.
131000304032302 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65500152016153.
The product of its (nonzero) digits is 1296, while the sum is 22.
Adding to 131000304032302 its reverse (203230403000131), we get a palindrome (334230707032433).
The spelling of 131000304032302 in words is "one hundred thirty-one trillion, three hundred four million, thirty-two thousand, three hundred two".
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