13100031000113 has 4 divisors (see below), whose sum is σ = 13100040326208. Its totient is φ = 13100021674020.

The previous prime is 13100031000109. The next prime is 13100031000131. The reversal of 13100031000113 is 31100013000131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 13100031000113 - 2² = 13100031000109 is a prime.

It is a super-2 number, since 2×13100031000113² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13100031000613) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2078573 + ... + 5524538.

It is an arithmetic number, because the mean of its divisors is an integer number (3275010081552).

Almost surely, 2^{13100031000113} is an apocalyptic number.

It is an amenable number.

13100031000113 is a deficient number, since it is larger than the sum of its proper divisors (9326095).

13100031000113 is an equidigital number, since it uses as much as digits as its factorization.

13100031000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9326094.

The product of its (nonzero) digits is 27, while the sum is 14.

Adding to 13100031000113 its reverse (31100013000131), we get a palindrome (44200044000244).

The spelling of 13100031000113 in words is "thirteen trillion, one hundred billion, thirty-one million, one hundred thirteen", and thus it is an aban number.