13100031210042 has 48 divisors (see below), whose sum is σ = 32510418033600. Its totient is φ = 3734530039296.

The previous prime is 13100031210023. The next prime is 13100031210067. The reversal of 13100031210042 is 24001213000131.

13100031210042 is a `hidden beast` number, since 1 + 310 + 0 + 0 + 312 + 1 + 0 + 0 + 42 = 666.

It is a super-2 number, since 2×13100031210042² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 13100031209997 and 13100031210024.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 115721268 + ... + 115834415.

It is an arithmetic number, because the mean of its divisors is an integer number (677300375700).

Almost surely, 2^{13100031210042} is an apocalyptic number.

13100031210042 is an abundant number, since it is smaller than the sum of its proper divisors (19410386823558).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13100031210042 is a wasteful number, since it uses less digits than its factorization.

13100031210042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 231556147 (or 231556144 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 13100031210042 its reverse (24001213000131), we get a palindrome (37101244210173).

The spelling of 13100031210042 in words is "thirteen trillion, one hundred billion, thirty-one million, two hundred ten thousand, forty-two".