Base | Representation |
---|---|
bin | 11101110010010011100011… |
… | …100111110110010111000111 |
3 | 122011211111201122012122100011 |
4 | 131302103203213312113013 |
5 | 114132302124234333221 |
6 | 1142340414501131051 |
7 | 36410314041266464 |
oct | 3562234347662707 |
9 | 564744648178304 |
10 | 131000321402311 |
11 | 38816a19295469 |
12 | 128388a66b9a87 |
13 | 581337b3032ba |
14 | 244c64118a66b |
15 | 102294414a1e1 |
hex | 7724e39f65c7 |
131000321402311 has 2 divisors, whose sum is σ = 131000321402312. Its totient is φ = 131000321402310.
The previous prime is 131000321402287. The next prime is 131000321402369. The reversal of 131000321402311 is 113204123000131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131000321402311 - 215 = 131000321369543 is a prime.
It is a super-2 number, since 2×1310003214023112 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131000321402381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500160701155 + 65500160701156.
It is an arithmetic number, because the mean of its divisors is an integer number (65500160701156).
Almost surely, 2131000321402311 is an apocalyptic number.
131000321402311 is a deficient number, since it is larger than the sum of its proper divisors (1).
131000321402311 is an equidigital number, since it uses as much as digits as its factorization.
131000321402311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 131000321402311 its reverse (113204123000131), we get a palindrome (244204444402442).
The spelling of 131000321402311 in words is "one hundred thirty-one trillion, three hundred twenty-one million, four hundred two thousand, three hundred eleven".
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