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13100040321 = 333521130267
BaseRepresentation
bin11000011001101001…
…01100000010000001
31020210222000222222120
430030310230002001
5203312102242241
610003523154453
7642426335244
oct141464540201
936728028876
1013100040321
1156126a4205
122657215a29
13130a02a964
148c3b6b25b
1551a113666
hex30cd2c081

13100040321 has 8 divisors (see below), whose sum is σ = 17467375584. Its totient is φ = 8733032640.

The previous prime is 13100040277. The next prime is 13100040323. The reversal of 13100040321 is 12304000131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13100040321 - 218 = 13099778177 is a prime.

It is a super-2 number, since 2×131000403212 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13100040321.

It is not an unprimeable number, because it can be changed into a prime (13100040323) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35430 + ... + 165696.

It is an arithmetic number, because the mean of its divisors is an integer number (2183421948).

Almost surely, 213100040321 is an apocalyptic number.

It is an amenable number.

13100040321 is a deficient number, since it is larger than the sum of its proper divisors (4367335263).

13100040321 is a wasteful number, since it uses less digits than its factorization.

13100040321 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 163791.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 13100040321 its reverse (12304000131), we get a palindrome (25404040452).

The spelling of 13100040321 in words is "thirteen billion, one hundred million, forty thousand, three hundred twenty-one".

Divisors: 1 3 33521 100563 130267 390801 4366680107 13100040321