1310004032419 has 2 divisors, whose sum is σ = 1310004032420. Its totient is φ = 1310004032418.

The previous prime is 1310004032413. The next prime is 1310004032431. The reversal of 1310004032419 is 9142304000131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1310004032419 - 2¹¹ = 1310004030371 is a prime.

It is a super-2 number, since 2×1310004032419² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1310004032413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655002016209 + 655002016210.

It is an arithmetic number, because the mean of its divisors is an integer number (655002016210).

Almost surely, 2^{1310004032419} is an apocalyptic number.

1310004032419 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310004032419 is an equidigital number, since it uses as much as digits as its factorization.

1310004032419 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 28.

The spelling of 1310004032419 in words is "one trillion, three hundred ten billion, four million, thirty-two thousand, four hundred nineteen".