131000410240003 has 2 divisors, whose sum is σ = 131000410240004. Its totient is φ = 131000410240002.

The previous prime is 131000410239971. The next prime is 131000410240043. The reversal of 131000410240003 is 300042014000131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131000410240003 - 2⁵ = 131000410239971 is a prime.

It is a super-2 number, since 2×131000410240003² (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131000410240043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500205120001 + 65500205120002.

It is an arithmetic number, because the mean of its divisors is an integer number (65500205120002).

Almost surely, 2^{131000410240003} is an apocalyptic number.

131000410240003 is a deficient number, since it is larger than the sum of its proper divisors (1).

131000410240003 is an equidigital number, since it uses as much as digits as its factorization.

131000410240003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 131000410240003 its reverse (300042014000131), we get a palindrome (431042424240134).

The spelling of 131000410240003 in words is "one hundred thirty-one trillion, four hundred ten million, two hundred forty thousand, three".