Base | Representation |
---|---|
bin | 10011000100000010010… |
… | …101011100001111010000 |
3 | 11122020100110000111012220 |
4 | 103010002111130033100 |
5 | 132430342033403100 |
6 | 2441450240221040 |
7 | 163434060656400 |
oct | 23040225341720 |
9 | 4566313014186 |
10 | 1310004200400 |
11 | 46562a246005 |
12 | 191a7990a780 |
13 | 966c092574c |
14 | 475940c2800 |
15 | 24122362aa0 |
hex | 1310255c3d0 |
1310004200400 has 180 divisors, whose sum is σ = 4881503626272. Its totient is φ = 299429518080.
The previous prime is 1310004200347. The next prime is 1310004200419. The reversal of 1310004200400 is 40024000131.
It is a super-2 number, since 2×13100042004002 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 1310004200400.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 11080692 + ... + 11198291.
Almost surely, 21310004200400 is an apocalyptic number.
1310004200400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1310004200400 is an abundant number, since it is smaller than the sum of its proper divisors (3571499425872).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1310004200400 is a wasteful number, since it uses less digits than its factorization.
1310004200400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22279018 (or 22279000 counting only the distinct ones).
The product of its (nonzero) digits is 96, while the sum is 15.
Adding to 1310004200400 its reverse (40024000131), we get a palindrome (1350028200531).
The spelling of 1310004200400 in words is "one trillion, three hundred ten billion, four million, two hundred thousand, four hundred".
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