13100044044012 has 12 divisors (see below), whose sum is σ = 30566769436056. Its totient is φ = 4366681348000.

The previous prime is 13100044043971. The next prime is 13100044044019. The reversal of 13100044044012 is 21044044000131.

It is a tau number, because it is divible by the number of its divisors (12).

It is a super-2 number, since 2×13100044044012² (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13100044044019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 545835168489 + ... + 545835168512.

It is an arithmetic number, because the mean of its divisors is an integer number (2547230786338).

Almost surely, 2^{13100044044012} is an apocalyptic number.

13100044044012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

13100044044012 is an abundant number, since it is smaller than the sum of its proper divisors (17466725392044).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13100044044012 is a wasteful number, since it uses less digits than its factorization.

13100044044012 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1091670337008 (or 1091670337006 counting only the distinct ones).

The product of its (nonzero) digits is 1536, while the sum is 24.

Adding to 13100044044012 its reverse (21044044000131), we get a palindrome (34144088044143).

The spelling of 13100044044012 in words is "thirteen trillion, one hundred billion, forty-four million, forty-four thousand, twelve".