13100044411 has 4 divisors (see below), whose sum is σ = 13186799824. Its totient is φ = 13013289000.

The previous prime is 13100044379. The next prime is 13100044423. The reversal of 13100044411 is 11444000131.

13100044411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11444000131 = 99809 ⋅114659.

It is a cyclic number.

It is not a de Polignac number, because 13100044411 - 2⁵ = 13100044379 is a prime.

It is a super-2 number, since 2×13100044411² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13100044211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43377480 + ... + 43377781.

It is an arithmetic number, because the mean of its divisors is an integer number (3296699956).

Almost surely, 2^13100044411 is an apocalyptic number.

13100044411 is a deficient number, since it is larger than the sum of its proper divisors (86755413).

13100044411 is an equidigital number, since it uses as much as digits as its factorization.

13100044411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 86755412.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 13100044411 its reverse (11444000131), we get a palindrome (24544044542).

The spelling of 13100044411 in words is "thirteen billion, one hundred million, forty-four thousand, four hundred eleven".