131000617435 has 4 divisors (see below), whose sum is σ = 157200740928. Its totient is φ = 104800493944.

The previous prime is 131000617421. The next prime is 131000617487. The reversal of 131000617435 is 534716000131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131000617435 - 2¹¹ = 131000615387 is a prime.

It is a super-2 number, since 2×131000617435² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131000617397 and 131000617406.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13100061739 + ... + 13100061748.

It is an arithmetic number, because the mean of its divisors is an integer number (39300185232).

Almost surely, 2^131000617435 is an apocalyptic number.

131000617435 is a deficient number, since it is larger than the sum of its proper divisors (26200123493).

131000617435 is an equidigital number, since it uses as much as digits as its factorization.

131000617435 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26200123492.

The product of its (nonzero) digits is 7560, while the sum is 31.

Adding to 131000617435 its reverse (534716000131), we get a palindrome (665716617566).

The spelling of 131000617435 in words is "one hundred thirty-one billion, six hundred seventeen thousand, four hundred thirty-five".