13100102123 has 2 divisors, whose sum is σ = 13100102124. Its totient is φ = 13100102122.

The previous prime is 13100102117. The next prime is 13100102129. The reversal of 13100102123 is 32120100131.

It is a balanced prime because it is at equal distance from previous prime (13100102117) and next prime (13100102129).

It is a cyclic number.

It is not a de Polignac number, because 13100102123 - 2¹² = 13100098027 is a prime.

It is a super-2 number, since 2×13100102123² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13100102098 and 13100102107.

It is not a weakly prime, because it can be changed into another prime (13100102129) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550051061 + 6550051062.

It is an arithmetic number, because the mean of its divisors is an integer number (6550051062).

Almost surely, 2^13100102123 is an apocalyptic number.

13100102123 is a deficient number, since it is larger than the sum of its proper divisors (1).

13100102123 is an equidigital number, since it uses as much as digits as its factorization.

13100102123 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 13100102123 its reverse (32120100131), we get a palindrome (45220202254).

The spelling of 13100102123 in words is "thirteen billion, one hundred million, one hundred two thousand, one hundred twenty-three".