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131001044199989 is a prime number
BaseRepresentation
bin11101110010010100001110…
…101101000110101000110101
3122011211120121000021120100112
4131302110032231012220311
5114132310114303344424
61142341014321152405
736410340666051365
oct3562241655065065
9564746530246315
10131001044199989
113881725a296017
1212838a6878b705
135813464c95332
14244c6ad17a9a5
15102298782260e
hex77250eb46a35

131001044199989 has 2 divisors, whose sum is σ = 131001044199990. Its totient is φ = 131001044199988.

The previous prime is 131001044199941. The next prime is 131001044200043. The reversal of 131001044199989 is 989991440100131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 71722978599364 + 59278065600625 = 8468942^2 + 7699225^2 .

It is a cyclic number.

It is not a de Polignac number, because 131001044199989 - 28 = 131001044199733 is a prime.

It is a super-2 number, since 2×1310010441999892 (a number of 29 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131001044196989) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500522099994 + 65500522099995.

It is an arithmetic number, because the mean of its divisors is an integer number (65500522099995).

Almost surely, 2131001044199989 is an apocalyptic number.

It is an amenable number.

131001044199989 is a deficient number, since it is larger than the sum of its proper divisors (1).

131001044199989 is an equidigital number, since it uses as much as digits as its factorization.

131001044199989 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2519424, while the sum is 59.

The spelling of 131001044199989 in words is "one hundred thirty-one trillion, one billion, forty-four million, one hundred ninety-nine thousand, nine hundred eighty-nine".