13100111011303 has 8 divisors (see below), whose sum is σ = 13742709950880. Its totient is φ = 12470236803360.

The previous prime is 13100111011291. The next prime is 13100111011349. The reversal of 13100111011303 is 30311011100131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13100111011303 is a prime.

It is a super-3 number, since 3×13100111011303³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13100111011373) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3181180800 + ... + 3181184917.

It is an arithmetic number, because the mean of its divisors is an integer number (1717838743860).

Almost surely, 2^{13100111011303} is an apocalyptic number.

13100111011303 is a deficient number, since it is larger than the sum of its proper divisors (642598939577).

13100111011303 is an equidigital number, since it uses as much as digits as its factorization.

13100111011303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6362365817.

The product of its (nonzero) digits is 27, while the sum is 16.

Adding to 13100111011303 its reverse (30311011100131), we get a palindrome (43411122111434).

The spelling of 13100111011303 in words is "thirteen trillion, one hundred billion, one hundred eleven million, eleven thousand, three hundred three".