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13100111113333 is a prime number
BaseRepresentation
bin1011111010100001101101…
…1110000010110001110101
31201101100200021020000100211
42332220123132002301311
53204113011421111313
643510035153105421
72521310652126436
oct276503336026165
951340607200324
1013100111113333
1141a07a92279a2
121576a80858271
137404484ccb9a
14334097b2b48d
1517ab6d51de3d
hexbea1b782c75

13100111113333 has 2 divisors, whose sum is σ = 13100111113334. Its totient is φ = 13100111113332.

The previous prime is 13100111113319. The next prime is 13100111113381. The reversal of 13100111113333 is 33331111100131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8714345328049 + 4385765785284 = 2952007^2 + 2094222^2 .

It is a cyclic number.

It is not a de Polignac number, because 13100111113333 - 213 = 13100111105141 is a prime.

It is a super-2 number, since 2×131001111133332 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13100111117333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550055556666 + 6550055556667.

It is an arithmetic number, because the mean of its divisors is an integer number (6550055556667).

Almost surely, 213100111113333 is an apocalyptic number.

It is an amenable number.

13100111113333 is a deficient number, since it is larger than the sum of its proper divisors (1).

13100111113333 is an equidigital number, since it uses as much as digits as its factorization.

13100111113333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 243, while the sum is 22.

Adding to 13100111113333 its reverse (33331111100131), we get a palindrome (46431222213464).

The spelling of 13100111113333 in words is "thirteen trillion, one hundred billion, one hundred eleven million, one hundred thirteen thousand, three hundred thirty-three".