Base | Representation |
---|---|
bin | 11101110010010100010010… |
… | …101111110111110000010011 |
3 | 122011211120202201220220120021 |
4 | 131302110102233313300103 |
5 | 114132310234140044243 |
6 | 1142341025143124311 |
7 | 36410342451455206 |
oct | 3562242257676023 |
9 | 564746681826507 |
10 | 131001112034323 |
11 | 38817294607a53 |
12 | 12838a87443697 |
13 | 58134760561ab |
14 | 244c6b819793d |
15 | 102298d7716ed |
hex | 772512bf7c13 |
131001112034323 has 2 divisors, whose sum is σ = 131001112034324. Its totient is φ = 131001112034322.
The previous prime is 131001112034321. The next prime is 131001112034327. The reversal of 131001112034323 is 323430211100131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131001112034323 - 21 = 131001112034321 is a prime.
It is a super-2 number, since 2×1310011120343232 (a number of 29 digits) contains 22 as substring.
Together with 131001112034321, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (131001112034321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500556017161 + 65500556017162.
It is an arithmetic number, because the mean of its divisors is an integer number (65500556017162).
Almost surely, 2131001112034323 is an apocalyptic number.
131001112034323 is a deficient number, since it is larger than the sum of its proper divisors (1).
131001112034323 is an equidigital number, since it uses as much as digits as its factorization.
131001112034323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 131001112034323 its reverse (323430211100131), we get a palindrome (454431323134454).
The spelling of 131001112034323 in words is "one hundred thirty-one trillion, one billion, one hundred twelve million, thirty-four thousand, three hundred twenty-three".
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