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131001112034323 is a prime number
BaseRepresentation
bin11101110010010100010010…
…101111110111110000010011
3122011211120202201220220120021
4131302110102233313300103
5114132310234140044243
61142341025143124311
736410342451455206
oct3562242257676023
9564746681826507
10131001112034323
1138817294607a53
1212838a87443697
1358134760561ab
14244c6b819793d
15102298d7716ed
hex772512bf7c13

131001112034323 has 2 divisors, whose sum is σ = 131001112034324. Its totient is φ = 131001112034322.

The previous prime is 131001112034321. The next prime is 131001112034327. The reversal of 131001112034323 is 323430211100131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131001112034323 - 21 = 131001112034321 is a prime.

It is a super-2 number, since 2×1310011120343232 (a number of 29 digits) contains 22 as substring.

Together with 131001112034321, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (131001112034321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500556017161 + 65500556017162.

It is an arithmetic number, because the mean of its divisors is an integer number (65500556017162).

Almost surely, 2131001112034323 is an apocalyptic number.

131001112034323 is a deficient number, since it is larger than the sum of its proper divisors (1).

131001112034323 is an equidigital number, since it uses as much as digits as its factorization.

131001112034323 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 131001112034323 its reverse (323430211100131), we get a palindrome (454431323134454).

The spelling of 131001112034323 in words is "one hundred thirty-one trillion, one billion, one hundred twelve million, thirty-four thousand, three hundred twenty-three".