Search a number
-
+
131001113030023 is a prime number
BaseRepresentation
bin11101110010010100010010…
…110011101010110110000111
3122011211120202210210111102001
4131302110102303222312013
5114132310234413430043
61142341025220330131
736410342463103135
oct3562242263526607
9564746683714361
10131001113030023
1138817295128045
1212838a87843947
135813476314472
14244c6b8376755
15102298d8bb74d
hex772512cead87

131001113030023 has 2 divisors, whose sum is σ = 131001113030024. Its totient is φ = 131001113030022.

The previous prime is 131001113030009. The next prime is 131001113030057. The reversal of 131001113030023 is 320030311100131.

It is a weak prime.

It is an emirp because it is prime and its reverse (320030311100131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131001113030023 is a prime.

It is a super-2 number, since 2×1310011130300232 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131001113030323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500556515011 + 65500556515012.

It is an arithmetic number, because the mean of its divisors is an integer number (65500556515012).

Almost surely, 2131001113030023 is an apocalyptic number.

131001113030023 is a deficient number, since it is larger than the sum of its proper divisors (1).

131001113030023 is an equidigital number, since it uses as much as digits as its factorization.

131001113030023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 131001113030023 its reverse (320030311100131), we get a palindrome (451031424130154).

The spelling of 131001113030023 in words is "one hundred thirty-one trillion, one billion, one hundred thirteen million, thirty thousand, twenty-three".