Base | Representation |
---|---|
bin | 11101110010010100010010… |
… | …110011101010110110000111 |
3 | 122011211120202210210111102001 |
4 | 131302110102303222312013 |
5 | 114132310234413430043 |
6 | 1142341025220330131 |
7 | 36410342463103135 |
oct | 3562242263526607 |
9 | 564746683714361 |
10 | 131001113030023 |
11 | 38817295128045 |
12 | 12838a87843947 |
13 | 5813476314472 |
14 | 244c6b8376755 |
15 | 102298d8bb74d |
hex | 772512cead87 |
131001113030023 has 2 divisors, whose sum is σ = 131001113030024. Its totient is φ = 131001113030022.
The previous prime is 131001113030009. The next prime is 131001113030057. The reversal of 131001113030023 is 320030311100131.
It is a weak prime.
It is an emirp because it is prime and its reverse (320030311100131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131001113030023 is a prime.
It is a super-2 number, since 2×1310011130300232 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131001113030323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500556515011 + 65500556515012.
It is an arithmetic number, because the mean of its divisors is an integer number (65500556515012).
Almost surely, 2131001113030023 is an apocalyptic number.
131001113030023 is a deficient number, since it is larger than the sum of its proper divisors (1).
131001113030023 is an equidigital number, since it uses as much as digits as its factorization.
131001113030023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 131001113030023 its reverse (320030311100131), we get a palindrome (451031424130154).
The spelling of 131001113030023 in words is "one hundred thirty-one trillion, one billion, one hundred thirteen million, thirty thousand, twenty-three".
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