13100114 has 4 divisors (see below), whose sum is σ = 19650174. Its totient is φ = 6550056.

The previous prime is 13100111. The next prime is 13100123. The reversal of 13100114 is 41100131.

13100114 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 11323225 + 1776889 = 3365^2 + 1333^2 .

It is a super-2 number, since 2×13100114² = 343225973625992, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13100095 and 13100104.

It is not an unprimeable number, because it can be changed into a prime (13100111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3275027 + ... + 3275030.

Almost surely, 2^13100114 is an apocalyptic number.

13100114 is a deficient number, since it is larger than the sum of its proper divisors (6550060).

13100114 is an equidigital number, since it uses as much as digits as its factorization.

13100114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6550059.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 13100114 is about 3619.4079626370. The cubic root of 13100114 is about 235.7355195704.

Adding to 13100114 its reverse (41100131), we get a palindrome (54200245).

The spelling of 13100114 in words is "thirteen million, one hundred thousand, one hundred fourteen".