Base | Representation |
---|---|
bin | 11000011001101001… |
… | …11111011111000011 |
3 | 1020210222012001021202 |
4 | 30030310333133003 |
5 | 203312112320003 |
6 | 10003525011415 |
7 | 642430116455 |
oct | 141464773703 |
9 | 36728161252 |
10 | 13100120003 |
11 | 5612749063 |
12 | 2657253b6b |
13 | 130a057cc9 |
14 | 8c3b8c2d5 |
15 | 51a12c088 |
hex | 30cd3f7c3 |
13100120003 has 4 divisors (see below), whose sum is σ = 13156343928. Its totient is φ = 13043896080.
The previous prime is 13100119999. The next prime is 13100120021. The reversal of 13100120003 is 30002100131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13100120003 - 22 = 13100119999 is a prime.
It is a super-2 number, since 2×131001200032 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13100120053) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28111613 + ... + 28112078.
It is an arithmetic number, because the mean of its divisors is an integer number (3289085982).
Almost surely, 213100120003 is an apocalyptic number.
13100120003 is a deficient number, since it is larger than the sum of its proper divisors (56223925).
13100120003 is an equidigital number, since it uses as much as digits as its factorization.
13100120003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56223924.
The product of its (nonzero) digits is 18, while the sum is 11.
Adding to 13100120003 its reverse (30002100131), we get a palindrome (43102220134).
The spelling of 13100120003 in words is "thirteen billion, one hundred million, one hundred twenty thousand, three".
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