Base | Representation |
---|---|
bin | 1011111010100001110000… |
… | …0101000011100110010111 |
3 | 1201101100200222110121010210 |
4 | 2332220130011003212113 |
5 | 3204113022030342221 |
6 | 43510040200220503 |
7 | 2521311135062625 |
oct | 276503405034627 |
9 | 51340628417123 |
10 | 13100121340311 |
11 | 41a0803a82645 |
12 | 1576a8416a733 |
13 | 74044a670b55 |
14 | 334099230515 |
15 | 17ab6e38e276 |
hex | bea1c143997 |
13100121340311 has 16 divisors (see below), whose sum is σ = 18228639340800. Its totient is φ = 8352608098560.
The previous prime is 13100121340231. The next prime is 13100121340373. The reversal of 13100121340311 is 11304312100131.
13100121340311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13100121340311 - 27 = 13100121340183 is a prime.
It is a super-2 number, since 2×131001213403112 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13100121360311) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11882785 + ... + 12938346.
It is an arithmetic number, because the mean of its divisors is an integer number (1139289958800).
Almost surely, 213100121340311 is an apocalyptic number.
13100121340311 is a deficient number, since it is larger than the sum of its proper divisors (5128518000489).
13100121340311 is a wasteful number, since it uses less digits than its factorization.
13100121340311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24828806.
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 13100121340311 its reverse (11304312100131), we get a palindrome (24404433440442).
The spelling of 13100121340311 in words is "thirteen trillion, one hundred billion, one hundred twenty-one million, three hundred forty thousand, three hundred eleven".
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