Base | Representation |
---|---|
bin | 10011000100000010110… |
… | …100000010001100101011 |
3 | 11122020101000002221022122 |
4 | 103010002310002030223 |
5 | 132430401112021303 |
6 | 2441451124141455 |
7 | 163434216100631 |
oct | 23040264021453 |
9 | 4566330087278 |
10 | 1310012220203 |
11 | 465633823445 |
12 | 191a8053788b |
13 | 966c24a2bab |
14 | 475951ad351 |
15 | 24122de8e38 |
hex | 13102d0232b |
1310012220203 has 8 divisors (see below), whose sum is σ = 1316016912000. Its totient is φ = 1304008691328.
The previous prime is 1310012220149. The next prime is 1310012220217. The reversal of 1310012220203 is 3020222100131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1310012220203 - 28 = 1310012219947 is a prime.
It is a super-2 number, since 2×13100122202032 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1310002220203) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2008973 + ... + 2579921.
It is an arithmetic number, because the mean of its divisors is an integer number (164502114000).
Almost surely, 21310012220203 is an apocalyptic number.
1310012220203 is a deficient number, since it is larger than the sum of its proper divisors (6004691797).
1310012220203 is a wasteful number, since it uses less digits than its factorization.
1310012220203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 581461.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 1310012220203 its reverse (3020222100131), we get a palindrome (4330234320334).
The spelling of 1310012220203 in words is "one trillion, three hundred ten billion, twelve million, two hundred twenty thousand, two hundred three".
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