Base | Representation |
---|---|
bin | 11000011001101010… |
… | …00001111011100111 |
3 | 1020210222012120000212 |
4 | 30030311001323213 |
5 | 203312113130043 |
6 | 10003525130035 |
7 | 642430160621 |
oct | 141465017347 |
9 | 36728176025 |
10 | 13100130023 |
11 | 5612755642 |
12 | 265725991b |
13 | 130a05c736 |
14 | 8c3b91c11 |
15 | 51a130018 |
hex | 30cd41ee7 |
13100130023 has 2 divisors, whose sum is σ = 13100130024. Its totient is φ = 13100130022.
The previous prime is 13100130007. The next prime is 13100130139. The reversal of 13100130023 is 32003100131.
It is a weak prime.
It is an emirp because it is prime and its reverse (32003100131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13100130023 - 24 = 13100130007 is a prime.
It is a super-2 number, since 2×131001300232 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13100139023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550065011 + 6550065012.
It is an arithmetic number, because the mean of its divisors is an integer number (6550065012).
Almost surely, 213100130023 is an apocalyptic number.
13100130023 is a deficient number, since it is larger than the sum of its proper divisors (1).
13100130023 is an equidigital number, since it uses as much as digits as its factorization.
13100130023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 13100130023 its reverse (32003100131), we get a palindrome (45103230154).
The spelling of 13100130023 in words is "thirteen billion, one hundred million, one hundred thirty thousand, twenty-three".
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