13100132023403 has 4 divisors (see below), whose sum is σ = 13100164017528. Its totient is φ = 13100100029280.

The previous prime is 13100132023399. The next prime is 13100132023421. The reversal of 13100132023403 is 30432023100131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13100132023403 - 2² = 13100132023399 is a prime.

It is a super-2 number, since 2×13100132023403² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13100132023423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15374813 + ... + 16204478.

It is an arithmetic number, because the mean of its divisors is an integer number (3275041004382).

Almost surely, 2^{13100132023403} is an apocalyptic number.

13100132023403 is a deficient number, since it is larger than the sum of its proper divisors (31994125).

13100132023403 is an equidigital number, since it uses as much as digits as its factorization.

13100132023403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31994124.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 13100132023403 its reverse (30432023100131), we get a palindrome (43532155123534).

The spelling of 13100132023403 in words is "thirteen trillion, one hundred billion, one hundred thirty-two million, twenty-three thousand, four hundred three".