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1310013320311 is a prime number
BaseRepresentation
bin10011000100000010111…
…000001110110001110111
311122020101002011211101101
4103010002320032301313
5132430401402222221
62441451203510531
7163434231332143
oct23040270166167
94566332154341
101310013320311
11465634404a23
12191a80988447
13966c2799847
14475953b8223
1524123064d91
hex13102e0ec77

1310013320311 has 2 divisors, whose sum is σ = 1310013320312. Its totient is φ = 1310013320310.

The previous prime is 1310013320249. The next prime is 1310013320323. The reversal of 1310013320311 is 1130233100131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1310013320311 - 27 = 1310013320183 is a prime.

It is a super-2 number, since 2×13100133203112 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310013320351) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655006660155 + 655006660156.

It is an arithmetic number, because the mean of its divisors is an integer number (655006660156).

Almost surely, 21310013320311 is an apocalyptic number.

1310013320311 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310013320311 is an equidigital number, since it uses as much as digits as its factorization.

1310013320311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1310013320311 its reverse (1130233100131), we get a palindrome (2440246420442).

The spelling of 1310013320311 in words is "one trillion, three hundred ten billion, thirteen million, three hundred twenty thousand, three hundred eleven".