131001341114041 has 8 divisors (see below), whose sum is σ = 131014517293800. Its totient is φ = 130988165529600.

The previous prime is 131001341114029. The next prime is 131001341114093. The reversal of 131001341114041 is 140411143100131.

It can be written as a sum of positive squares in 4 ways, for example, as 75581654200441 + 55419686913600 = 8693771^2 + 7444440^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 131001341114041 - 2⁹ = 131001341113529 is a prime.

It is a super-2 number, since 2×131001341114041² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131001341113997 and 131001341114015.

It is not an unprimeable number, because it can be changed into a prime (131001341114741) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 531691365 + ... + 531937693.

It is an arithmetic number, because the mean of its divisors is an integer number (16376814661725).

Almost surely, 2^{131001341114041} is an apocalyptic number.

It is an amenable number.

131001341114041 is a deficient number, since it is larger than the sum of its proper divisors (13176179759).

131001341114041 is a wasteful number, since it uses less digits than its factorization.

131001341114041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 297659.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 131001341114041 its reverse (140411143100131), we get a palindrome (271412484214172).

The spelling of 131001341114041 in words is "one hundred thirty-one trillion, one billion, three hundred forty-one million, one hundred fourteen thousand, forty-one".