131001341114040 has 32 divisors (see below), whose sum is σ = 393004023342480. Its totient is φ = 34933690963712.

The previous prime is 131001341114029. The next prime is 131001341114093. The reversal of 131001341114040 is 40411143100131.

It is a super-2 number, since 2×131001341114040² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a self number, because there is not a number n which added to its sum of digits gives 131001341114040.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 545838921189 + ... + 545838921428.

Almost surely, 2^{131001341114040} is an apocalyptic number.

131001341114040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131001341114040 is an abundant number, since it is smaller than the sum of its proper divisors (262002682228440).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131001341114040 is a wasteful number, since it uses less digits than its factorization.

131001341114040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1091677842631 (or 1091677842627 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 24.

Adding to 131001341114040 its reverse (40411143100131), we get a palindrome (171412484214171).

The spelling of 131001341114040 in words is "one hundred thirty-one trillion, one billion, three hundred forty-one million, one hundred fourteen thousand, forty".