131001401099963 has 2 divisors, whose sum is σ = 131001401099964. Its totient is φ = 131001401099962.

The previous prime is 131001401099951. The next prime is 131001401100007. The reversal of 131001401099963 is 369990104100131.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131001401099963 is a prime.

It is a super-2 number, since 2×131001401099963² (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131001401089963) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500700549981 + 65500700549982.

It is an arithmetic number, because the mean of its divisors is an integer number (65500700549982).

Almost surely, 2^{131001401099963} is an apocalyptic number.

131001401099963 is a deficient number, since it is larger than the sum of its proper divisors (1).

131001401099963 is an equidigital number, since it uses as much as digits as its factorization.

131001401099963 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 157464, while the sum is 47.

The spelling of 131001401099963 in words is "one hundred thirty-one trillion, one billion, four hundred one million, ninety-nine thousand, nine hundred sixty-three".